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A Levels Physics (9702)•9702/11/M/J/22
Question 24 from 9702/11/M/J/22

Explanation

Doppler Effect for Approaching Source

Steps:

  • Identify the scenario: source (horn) moves toward stationary observer (man) at constant velocity.
  • Recall Doppler formula: observed frequency f′=fvv−vsf' = f \frac{v}{v - v_s}f′=fv−vs​v​, where fff is emitted frequency, vvv is sound speed, vsv_svs​ is source speed (positive toward observer).
  • Since vs>0v_s > 0vs​>0, f′>ff' > ff′>f; higher frequency means shorter wavelength (λ′=vf′<λ=vf\lambda' = \frac{v}{f'} < \lambda = \frac{v}{f}λ′=f′v​<λ=fv​).
  • Conclude wavelength heard is shorter.

Why D is correct:

  • For approaching source, waves compress, reducing wavelength while increasing frequency, per Doppler principle.

Why the others are wrong:

  • A: Incorrect; heard frequency exceeds emitted frequency due to bunching of waves.
  • B: Incorrect; frequency is constant for steady velocity, independent of distance.
  • C: Incorrect; sound waves travel at constant speed vvv; no acceleration occurs.

Final answer: D

Topic: Doppler effect for sound waves

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