Wave frequency and amplitude from displacement-time graph

Steps:

• Measure the time for one complete oscillation (period T) from the graph's waveform.
• Calculate frequency f = 1/T; for T = 10 ns, f = 100 MHz.
• Identify amplitude as the maximum displacement from the equilibrium position, which is 5 mm.
• Confirm units: frequency in MHz, amplitude in mm.

Why A is correct:

• Frequency is 1/period per the wave equation, and amplitude is half the peak-to-peak displacement by definition.

Why the others are wrong:

• B: Incorrect frequency; period is 10 ns, not 5 ns.
• C: Incorrect amplitude; maximum displacement is 5 mm, not 10 mm.
• D: Incorrect both; misreads period and amplitude.

Final answer: A