Diffraction maximized when feature size matches wavelength

Steps:

• Calculate wavelength: λ = v / f = 350 m/s / 0.44 Hz ≈ 795 m.
• Diffraction of sound waves is strongest when architectural feature size is comparable to λ.
• Compare options: A (1.3 mm) and C/D (7.5 m, 17 m) are much smaller than 795 m; B (750 m) is closest.
• Select B as the best match for optimal diffraction.

Why B is correct:

• 750 m ≈ λ (795 m), per the diffraction principle that waves bend significantly around obstacles of similar size to their wavelength.

Why the others are wrong:

• A: 1.3 mm << λ, so sound passes over features with negligible diffraction (reflection dominates).
• C: 7.5 m is ~100 times smaller than λ, insufficient for effective diffraction.
• D: 17 m is ~50 times smaller than λ, still too small for strong diffraction.

Final answer: B