Voltage drop in supply wires reduces power delivered to kettle

Steps:

• Calculate supply current: I = P/V = 2400 W / 240 V = 10 A.
• Total wire resistance: 0.50 Ω + 0.50 Ω = 1.0 Ω.
• Voltage drop across wires: V_drop = I × R_wires = 10 A × 1.0 Ω = 10 V.
• p.d. across kettle: 240 V - 10 V = 230 V; power to kettle: 230 V × 10 A = 2.3 kW.

Why A is correct:

• Applies Ohm's law (V = IR) and power formula (P = VI) to account for resistive losses in series wires.

Why the others are wrong:

• B: Underestimates voltage drop (uses 5 V instead of 10 V).
• C: Ignores power loss in wires (assumes full 2.4 kW delivered).
• D: Identical to C; ignores power loss.

Final answer: A