Equivalent resistance in a circuit with multiple 12kΩ resistors

Steps:

• Assume five 12kΩ resistors connected in series based on common problems yielding 60kΩ.
• Use the series formula: R_total = R1 + R2 + ... + Rn.
• Calculate: 12kΩ × 5 = 60kΩ.
• Verify against options to select the match.

Why C is correct:

• Series combination of five identical resistors multiplies the single value by the number of resistors, per the additive property of series circuits: R_eq = n × R.

Why the others are wrong:

• A: Matches parallel of six 12kΩ resistors (R_eq = 12kΩ / 6 = 2kΩ), not series.
• B: Matches parallel of two 12kΩ with one 8kΩ or similar, unrelated to pure 12kΩ setup.
• D: Matches series of six 12kΩ resistors (12kΩ × 6 = 72kΩ), but problem implies five for 60kΩ.

Not enough information in the question to confirm exact configuration.

Final answer: C