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A Levels Physics (9702)•9702/11/M/J/21
Question 23 from 9702/11/M/J/21

Explanation

Antinodes in standing wave separated by λ/2

Steps:

  • Positions of maximum loudness are antinodes in the standing sound wave.
  • Moving from first to fourth antinode spans 3 intervals.
  • Distance = 3 × (λ/2) = 0.12 m, so λ = (2 × 0.12 m) / 3 = 0.08 m.
  • Frequency f = v / λ = 300 m/s / 0.08 m ≈ 4100 Hz.

Why A is correct:

  • Matches f = 3v / (2 × distance) from standing wave antinode spacing of λ/2.

Why the others are wrong:

  • B. Uses 4 intervals instead of 3, giving f ≈ 5000 Hz.
  • C. Uses 6 intervals instead of 3, giving f ≈ 7500 Hz.
  • D. Uses 8 intervals instead of 3, giving f ≈ 10000 Hz.

Final answer: A

Topic: Stationary waves

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