Vertical displacement under gravity

Steps:

• Use displacement formula for free fall or projectile: $s = ut \pm \frac{1}{2}gt^2$, where $u$ is initial velocity, $g \approx 10 \, \mathrm{m/s^2}$, $t = 3 \, \mathrm{s}$.
• Assume starting from ground ($s_0 = 0$), but direction (up/down) and $u$ are unspecified.
• Without $u$, numerical calculation impossible; standard assumptions (e.g., dropped) yield $s = 45 \, \mathrm{m}$, not matching choices directly.
• Conclude insufficient data to determine exact displacement.

Not enough information.

Why A is correct:

• Cannot verify; lacks supporting details like initial velocity.

Why the others are wrong:

• B: Exceeds typical free-fall distance of ~45 m.
• C: Matches half of free-fall but arbitrary without $u$.
• D: Equals $\frac{1}{2}gt^2 = 45 \, \mathrm{m}$ for dropped ball, but problem ambiguous.

Final answer: Not enough information.