A Levels Physics (9702)•9702/12/M/J/20

Explanation
Phase difference of 90° in transverse waves
Steps:
- Points X and Y separated by λ/4 have a phase difference of π/2 radians.
- Displacement at X: y_X = A sin(θ), where θ = ωt + φ.
- Displacement at Y: y_Y = A sin(θ + π/2) = A cos(θ).
- Analyze possibilities using trigonometric identities like sin²θ + cos²θ = 1.
Why A is correct:
- Both having zero displacement requires sin θ = 0 and cos θ = 0, which is impossible since sin²θ + cos²θ = 1 ≠ 0.
Why the others are wrong:
- B: Opposite directions possible (e.g., sin θ = 0.707, cos θ = -0.707).
- C: Same magnitude possible (e.g., |sin θ| = |cos θ| = √2/2 at θ = π/4).
- D: Same magnitude possible (e.g., |sin θ| = |cos θ| = √2/2 at θ = π/4).
Final answer: A
Topic: Transverse and longitudinal waves
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