Circuit voltage distribution Steps:

• Assume two identical cells in series, providing total emf 2E.
• Lamp 1 connects across both cells, receiving voltage 2E.
• Lamp 2 connects across the first cell, receiving voltage E.
• Lamp 3 connects across the second cell, receiving voltage E. Why C is correct:
• Lamps 2 and 3 each get full emf E; by Ohm's law, V = IR yields normal current I = E/R for brightness. Why the others are wrong:
• A: Lamp 1 gets 2E, so brighter than normal.
• B: Lamp 1 gets 2E (brighter), not normal.
• D: Lamps 2 and 3 get E, so normal brightness. Final answer: C