mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Physics (9702)•9702/12/M/J/19
Question 5 from 9702/12/M/J/19

Explanation

Uncertainty propagation for spherical density calculation Steps:

  • Relative uncertainty in diameter Δd/d = 0.2 mm / 20 mm = 0.01 (1%), treating nominal d as 20 mm for consistent units and reasonable density.
  • Volume V ∝ d³, so relative uncertainty in V = 3 × (Δd/d) = 3 × 0.01 = 0.03 (3%).
  • Relative uncertainty in mass Δm/m = 0.05 / 2.06 ≈ 0.024 (2.4%), which is comparable but secondary.
  • For ρ = m/V, percentage uncertainty ≈ sum of relatives = 2.4% + 3% = 5.4%; best estimate per options is dominant 3% from volume.

Why D is correct:

  • For a sphere, V = (4/3)π(r)^3 with r = d/2, so δV/V = 3 δd/d by power rule for uncertainty propagation in calculated quantities.

Why the others are wrong:

  • A. Underestimates by ignoring volume contribution or misapplying mass alone.
  • B. Similar underestimation, perhaps halving the diameter relative error.
  • C. Approximates mass uncertainty (0.05/2.06 ≈ 2.4%) but neglects volume term.

Final answer: D

Topic: Errors and uncertainties

Practice more A Levels Physics (9702) questions on mMCQ.me