Torque equilibrium in cranes Steps:

• Weight of counterweight: 5000 kg × 9.8 m/s² = 49,000 N.
• Load weight: 12.0 kN = 12,000 N.
• Torque balance: counterweight torque = load torque, so 49,000 N × d = 12,000 N × 17.0 m.
• Solve for d: d = (12,000 × 17.0) / 49,000 ≈ 4.16 m. Why C is correct:
• Matches torque equilibrium formula (∑τ = 0), balancing moments about pivot. Why the others are wrong:
• A: Too small; ignores proper weight calculation, underbalancing load torque.
• B: Far too small; misapplies masses without gravity conversion.
• D: Approximate value using g=10 m/s²; not precise for g=9.8 m/s².

Final answer: C