Kinematic equation for maximum height

Steps:

• At maximum height, final velocity is 0 m/s.
• Apply $v^2 = u^2 + 2as$, with $v = 0$, $u = 9$ m/s, $s = 12$ m, $a = -g$.
• $0 = 9^2 - 2g \times 12$.
• $24g = 81$, so $g = 81 / 24 = 3.375$ m/s² ≈ 3.7 m/s².

Why B is correct:

• Matches the calculated $g \approx 3.7$ m/s² from $g = u^2 / (2h)$, consistent with Mars gravity.

Why the others are wrong:

• A is too small; underestimates deceleration needed for 12 m rise.
• C is twice Earth's g/2.6; overestimates Mars gravity.
• D is Earth's g; ignores lower Mars gravity.

Final answer: B