mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Physics (9702)•9702/12/M/J/18
Question 39 from 9702/12/M/J/18

Explanation

Neutrons in nuclides = mass number - atomic number

Steps:

  • Identify atomic numbers: radon (Rn) = 86, francium (Fr) = 87, radium (Ra) = 88.
  • For Rn-211: neutrons = 211 - 86 = 125.
  • For Fr-210: neutrons = 210 - 87 = 123.
  • For Ra-212: neutrons = 212 - 88 = 124.

Why B is correct:

  • B gives 125, 123, 124, matching the formula N = A - Z for each nuclide.

Why the others are wrong:

  • A: Uses incorrect differences (e.g., 211 - 83 = 128, mistaking Rn's Z).
  • C: Lists mass numbers A, which include protons and neutrons.
  • D: Yields impossible values exceeding reasonable nuclear sizes.

Final answer: B

Topic: Atoms, nuclei and radiation

Practice more A Levels Physics (9702) questions on mMCQ.me