Power loss in supply wires reduces voltage and power to the kettle

Steps:

• Supply current: I = P/V = 2400 W / 240 V = 10 A.
• Total wire resistance: 0.50 Ω + 0.50 Ω = 1.0 Ω.
• Voltage drop in wires: V_drop = I × R = 10 A × 1.0 Ω = 10 V; kettle p.d. = 240 V - 10 V = 230 V.
• Kettle power: P_k = V_k × I = 230 V × 10 A = 2300 W = 2.3 kW.

Why A is correct:

• Matches Ohm's law (V = IR) for voltage drop and P = VI for reduced power delivery.

Why the others are wrong:

• B: Correct power but voltage drop is 10 V, not 5 V.
• C: Ignores power loss in wires (I²R = 100 W) and underestimates voltage drop.
• D: Same errors as C in power and voltage.

Final answer: A