Energy used proportional to distance, time from power input

Steps:

• Full range uses 200 MJ for 150 km, so energy per km = 200 / 150 = 4/3 MJ/km.
• Distance driven = 100 km, so energy used = 100 × (4/3) = 400/3 MJ ≈ 133.3 MJ.
• Charging power = 230 V × 13 A = 2990 W = 2.99 kJ/s.
• Time = (400/3 × 10^6 J) / 2990 s ≈ 44,615 s ≈ 12.4 hours.

Why B is correct:

• Time equals energy depleted divided by charging power (P = VI, t = E/P).

Why the others are wrong:

• A: Underestimates by assuming full recharge or wrong power.
• C: Overestimates by using full 200 MJ instead of 133.3 MJ.
• D: Overestimates further, possibly ignoring efficiency or miscalculating power.

Final answer: B