mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Physics (9702)•9702/12/M/J/18
Question 10 from 9702/12/M/J/18

Explanation

Mixture density via mass conservation

Steps:

  • Mass of glycerine: 1.3 g/cm³ × 40 cm³ = 52 g.
  • Let volume of water added be V cm³; its mass is 1 g/cm³ × V = V g.
  • Total mass = 52 g + V g; total volume = 40 cm³ + V cm³.
  • Set up equation: (52 + V) / (40 + V) = 1.1; solve to get V = 80 cm³.

Why D is correct:

  • The density formula for mixtures (total mass / total volume) directly yields 80 cm³ when solved, assuming additive volumes.

Why the others are wrong:

  • A: 40 cm³ gives density 1.15 g/cm³, higher than 1.1 g/cm³.
  • B: 44 cm³ gives density ≈1.14 g/cm³, higher than 1.1 g/cm³.
  • C: 52 cm³ gives density ≈1.13 g/cm³, higher than 1.1 g/cm³.

Final answer: D

Topic: Density and pressure

Practice more A Levels Physics (9702) questions on mMCQ.me