Catalytic converter reaction limits product volume by CO

Steps:

• Reaction: 2NO + 2CO → N₂ + 2CO₂ (1:1 molar ratio of NO to CO).
• Moles NO: 23 g / 30 g/mol = 0.767 mol; moles CO: 7 g / 28 g/mol = 0.25 mol.
• CO is limiting (0.25 mol CO requires 0.25 mol NO); produces 0.125 mol N₂ and 0.25 mol CO₂.
• Total product moles: 0.375 mol; at room conditions (24 dm³/mol), volume = 0.375 × 24 = 9.0 dm³.

Why C is correct:

• Matches total moles of N₂ and CO₂ from limiting reactant, using ideal gas volume at RTP (24 dm³/mol).

Why the others are wrong:

• A: Assumes only N₂ volume, ignoring CO₂.
• B: Equals CO moles volume, missing reaction stoichiometry.
• D: Assumes excess NO reacts fully, overestimating products.

Final answer: C