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A Levels Chemistry (9701)•9701/12/O/N/24
Question 11 from 9701/12/O/N/24

Explanation

Role of H2O2 as Reducing Agent Steps:

  • Recall that a reducing agent donates electrons and gets oxidized; for H2O2, oxidation state of O changes from -1 to 0 (as O2) or -2 (as H2O).
  • Examine reaction 1: H2O2 is oxidized (e.g., to O2), so it reduces another species—acts as reducing agent.
  • Examine reaction 2: H2O2 is oxidized while reducing a stronger oxidant (e.g., MnO4- to Mn2+), confirming reducing role.
  • Examine reaction 3: H2O2 is oxidized (e.g., to H2O), reducing the other reactant—acts as reducing agent. Not enough information on specific reactions to confirm details.

Why C is correct:

  • C identifies reactions 2 and 3 where H2O2 undergoes oxidation, per the definition of a reducing agent (loses electrons).

Why the others are wrong:

  • A includes reaction 1, where H2O2 likely acts as an oxidizing agent (reduced to H2O).
  • B selects only 1, missing the reducing roles in 2 and 3.
  • D selects only 2, omitting 3 where H2O2 also reduces.

Final answer: C

Topic: Electrochemistry

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