Alcohol oxidation yields unique products based on primary, secondary, or tertiary classification

Steps:

• Classify each alcohol: primary (1°), secondary (2°), or tertiary (3°).
• Recall that 1° alcohols oxidize to aldehydes then carboxylic acids (two products); 2° to ketones (one product); 3° do not oxidize.
• Apply to options: check if dilute acidified K2Cr2O7 conditions allow full oxidation for 1° alcohols.
• Identify the alcohol with exactly one product.

Why B is correct:

• Butan-2-ol (CH3CH(OH)CH2CH3) is secondary and oxidizes solely to butan-2-one (CH3COCH2CH3), per the rule that secondary alcohols form one ketone.

Why the others are wrong:

• A: Butan-1-ol is primary, yielding butanal then butanoic acid (two products).
• C: 2-Methylpropan-1-ol is primary, yielding 2-methylpropanal then 2-methylpropanoic acid (two products).
• D: 2-Methylpropan-2-ol is tertiary, yielding no oxidation product.

Final answer: B