Empirical formula from skeletal structure

Steps:

• Examine the skeletal diagram to count C and N atoms directly visible.
• Infer H atoms to satisfy valences: each C bonds to 4, each N to 3, with bonds shown.
• Write molecular formula from total atom counts.
• Divide counts by greatest common divisor for simplest whole-number ratio.

Why B is correct:

• The atom ratio C:H:N simplifies to 1:2:1 per the empirical formula definition as lowest whole-number proportions.

Why the others are wrong:

• A: Implies 1:3:1 ratio, exceeding H count from valences.
• C: Implies 1:4:1 ratio, overestimating H for tetravalent C.
• D: Implies 1:6:2 ratio, including extra N not present.

Final answer: B