
Explanation
Standard Enthalpy of Neutralisation Defined by Water Formation Steps: - Recall that neutralisation involves acid-base reactions producing water and salt in aqueous solution. - Identify the standard condition: ΔH° measures enthalpy change under standard conditions (298 K, 1 atm). - Focus on the key outcome: the reaction always forms H₂O from H⁺(aq) + OH⁻(aq) → H₂O(l), with ΔH° ≈ -57 kJ/mol for strong acid-strong base. - Compare options: select the one specifying one mole of water as the product, as this standardises the measurement regardless of acid/base amounts. Why D is correct: - By definition, ΔH°_neut is the enthalpy change when one mole of water forms from the reaction of aqueous H⁺ and OH⁻ ions, making it consistent for all strong acid-strong base neutralisations. Why the others are wrong: - A: Omits specifying the amount of alkali, so it doesn't standardise to one mole of water. - B: Focuses on alkali first but still lacks quantification for one mole of water produced. - C: Specifies equal moles of acid and alkali but ignores that the enthalpy is defined per mole …
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