Nucleophilic substitution to primary alcohol followed by oxidation to carboxylic acid

Steps:

• 1-Bromopropane (CH₃CH₂CH₂Br) undergoes SN2 reaction with OH⁻ to form propan-1-ol (CH₃CH₂CH₂OH).
• Propan-1-ol, a primary alcohol, is oxidized by acidified KMnO₄ to propanoic acid (CH₃CH₂COOH).

Why A is correct:

• Primary alcohols oxidize to carboxylic acids via two-stage process (aldehyde intermediate then acid), as per organic oxidation rules.

Why the others are wrong:

• B: Propanone (ketone) requires secondary alcohol precursor, not primary from 1-bromopropane.
• C: Propylamine forms via SN2 with NH₃, but no oxidation step applies.
• D: Propyl ethanoate is an ester from alcohol acylation with ethanoic acid, not oxidation.

Final answer: A