A Levels Chemistry (9701)•9701/13/O/N/21

Explanation
Fifth ionization energy highest for core electron removal from innermost shell
Steps:
- Determine valence electrons: C and Si have 4 (group 14), N and P have 5 (group 15).
- For C and Si, first 4 IEs remove valence electrons, fifth targets core electrons.
- For N and P, fifth IE removes a valence electron from p orbital.
- Core removal from C's 1s shell requires more energy than Si's 2p or valence p orbitals due to nuclear proximity.
Why A is correct:
- Carbon's fifth IE removes a 1s core electron, tightly bound by the nucleus per Coulomb's law, demanding highest energy.
Why the others are wrong:
- B. Nitrogen's fifth IE removes a 2p valence electron, less bound than core.
- C. Phosphorus's fifth IE removes a 3p valence electron, shielded and farther from nucleus.
- D. Silicon's fifth IE removes a 2p core electron, less tightly held than carbon's 1s.
Final answer: A
Topic: The Periodic Table: chemical periodicity
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