Reactions producing water from propan-1-ol

Steps:

• Recall propan-1-ol (CH₃CH₂CH₂OH) undergoes dehydration, esterification, and substitution reactions.
• Analyze option A: Vapor over hot Al₂O₃ causes dehydration to propene + H₂O.
• Analyze option B: With ethanoic acid + H₂SO₄ forms ester + H₂O via esterification.
• Analyze option C: With HBr + H₂SO₄ forms bromopropane + H₂O via substitution.
• Note D is missing, making full analysis impossible.

Why A is correct:

• Dehydration of alcohols over hot alumina follows CH₃CH₂CH₂OH → CH₃CH=CH₂ + H₂O, eliminating water.

Why the others are wrong:

• B: Esterification also produces water (CH₃CH₂CH₂OH + CH₃COOH → CH₃CH₂CH₂OC(O)CH₃ + H₂O).
• C: Substitution also produces water (CH₃CH₂CH₂OH + HBr → CH₃CH₂CH₂Br + H₂O).
• D: Not enough information.

Final answer: A, B, and C