Counting stereoisomers of C3H7ClO alcohols excluding X, Y, Z

Steps:

• Identify 5 structural alcohol isomers: 1-chloropropan-1-ol [CH3CH2CH(Cl)OH, chiral], 2-chloropropan-1-ol [CH3CHClCH2OH, chiral], 3-chloropropan-1-ol [ClCH2CH2CH2OH, achiral], 1-chloropropan-2-ol [CH3CH(OH)CH2Cl, chiral], 2-chloropropan-2-ol [(CH3)2C(Cl)OH, achiral].
• Count stereoisomers: 2 (first) + 2 (second) + 1 (third) + 2 (fourth) + 1 (fifth) = 8 total.
• X, Y, Z represent 3 distinct isomers from this set.
• Subtract to find others: 8 - 3 = 5.

Why D is correct:

• Molecular formula C3H7ClO allows 5 structural alcohols, with 3 chiral centers each yielding 2 enantiomers, totaling 8 stereoisomers per isomerism definition.

Why the others are wrong:

• A: Ignores all stereoisomers, counting only 5 structures.
• B: Counts structures plus one chiral pair but misses others.
• C: Includes all structures and two chiral pairs but omits the third.

Final answer: D