Iodoform test identifies specific alcohols Steps:

• Recognize the yellow precipitate as iodoform (CHI₃) from reaction with I₂/NaOH.
• Alcohols giving the test are those oxidizable to CH₃CHO (ethanol) or CH₃COR (methyl ketones from CH₃CH(OH)R).
• Analyze structures: primary alcohols without CH₃CH₂OH structure or secondary without CH₃CH(OH)R fail.
• Identify matching option: CH₃CH(OH)CH₃ fits CH₃CH(OH)R, oxidizes to CH₃COCH₃.

Why C is correct:

• CH₃CH(OH)CH₃ (propan-2-ol) oxidizes to acetone (CH₃COCH₃), a methyl ketone that undergoes iodoform reaction per the test's structural requirement.

Why the others are wrong:

• A: (CH₃)₂CHOH is identical to C (propan-2-ol), but if distinct, it matches and would give test—likely duplicate.
• B: CH₃CH₂CH₂OH (propan-1-ol) oxidizes to propanal (CH₃CH₂CHO), lacking CH₃C=O group.
• D: CH₃CH₂CH₂OH identical to B, oxidizes to propanal, no iodoform reaction.

Final answer: C