A Levels Chemistry (9701)•9701/12/O/N/19
Explanation
Esterification reaction identifies acid and alcohol for ester Z
Steps:
- Recall esterification: carboxylic acid (RCOOH) + alcohol (R'OH) → ester (RCOOR') + H2O.
- Determine ester Z's structure: butanoate group from butanoic acid (C3H7COOH) and propan-2-yl from propan-2-ol ((CH3)2CHOH).
- Match choices: select acid providing carbonyl chain and alcohol providing alkoxy group.
- Verify: butanoic acid + propan-2-ol yields propan-2-yl butanoate (Z).
Why C is correct:
- C combines butanoic acid (four carbons in chain) and propan-2-ol (branched three-carbon alcohol), forming the ester with butanoate and 1-methylethoxy groups.
Why the others are wrong:
- A: Yields propyl butanoate, wrong chain lengths.
- B: Yields butyl propanoate, swapped acid/alcohol chains.
- D: Yields 1-methylethyl propanoate, shorter acid chain.
Not enough information: Ester Z's structure or name is not provided, preventing full verification.
Final answer: C
Topic: Carboxylic acids and derivatives
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