Oxidative cleavage by hot, concentrated acidified KMnO4 yields one product from symmetrical alkenes

Steps:

• Identify the reaction: Hot, concentrated acidified KMnO4 cleaves C=C bonds in alkenes to carbonyl compounds (ketones or CO2/COOH).
• Determine product condition: A single carbon-containing product implies complete oxidation to CO2 or HCOOH from a symmetrical structure with equivalent carbons.
• Evaluate options: All choices are CH3CH2CH3 (propane, an alkane), which resists oxidation under these conditions, yielding no defined products.
• Conclude ambiguity: Identical options provide no distinction, making selection impossible.

Why B is correct:

• Not enough information; all options identical, but specified as B without differentiation.

Why the others are wrong:

• A: Identical to B, alkane not cleaved to single product.
• C: Identical to B, alkane not cleaved to single product.
• D: Identical to B, alkane not cleaved to single product.

Final answer: Not enough information.