Oxidative cleavage of alkenes with KMnO4 Steps:

• Hot, concentrated, acidified KMnO4 oxidatively cleaves the C=C bond, converting =CR2 to ketone RCOR, =CHR to carboxylic acid RCOOH, and =CH2 to CO2.
• The reaction yields a single organic product, indicating the alkene is symmetric so both cleavage fragments are identical.
• Examine each option: identify the alkene's substitution pattern and predict cleavage products.
• Match the option that produces only one unique organic compound.

Why D is correct:

• D is a symmetric alkene (e.g., (CH3)2C=C(CH3)2), cleaving to two molecules of acetone (CH3)2C=O, a single product per the reaction rule for identical fragments.

Why the others are wrong:

• A: Unsymmetric (e.g., CH3CH=CHCH3), yields two different aldehydes/ketones.
• B: Terminal alkene (e.g., CH2=CH2), produces CO2 and no organic product.
• C: Unsymmetric disubstituted (e.g., CH3CH=CH2), yields acetic acid and CO2, not a single organic product.

Final answer: D