Mild oxidation of butan-2-one with KMnO₄ Steps:

• Identify Q as butan-2-one, CH₃C(O)CH₂CH₃, an unsymmetrical ketone.
• Note cold, dilute, acidified manganate(VII) acts as a mild oxidant targeting the terminal methyl in the ethyl group.
• Oxidation converts -CH₂CH₃ to -CH₂CH₂OH, preserving the carbonyl.
• Resulting product CH₃C(O)CH₂CH₂OH matches option C. Why C is correct:
• Cold, dilute, acidified KMnO₄ selectively oxidizes the primary carbon in the alkyl chain of methyl ketones to a primary alcohol, per standard organic oxidation rules. Why the others are wrong:
• A: Butan-2-one has no C=C bond for addition polymerization; repeat unit suggests vinyl monomer like methyl acrylate.
• B: Alpha-chlorination of ketones uses electrophilic mechanism with Cl₂/acid, not free radical.
• D: Alpha-bromination of ketones is electrophilic, not free radical with Br₂. Final answer: C