A Levels Chemistry (9701)•9701/12/O/N/18

Explanation
Structural Isomers of Butane (C4H10)
Steps:
- Confirm alkane formula CnH2n+2 gives C4H10 for n=4, requiring only carbon and hydrogen with different connectivities.
- Identify the two isomers: straight-chain n-butane (CH3CH2CH2CH3) and branched 2-methylpropane (CH3CH(CH3)CH3 or (CH3)3CH).
- Verify option formulas match C4H10 by counting atoms and ensuring hydrocarbon structure.
- Eliminate options with incorrect atom counts or non-alkane structures.
Why A is correct:
- All formulas are C4H10 alkanes; CH3CH2CH2CH3 is n-butane, while CH3CH(CH3)CH3 and (CH3)3CH both depict the branched isomer with different notation.
Why the others are wrong:
- B includes CH3CH2CH3 (C3H8, propane) and CH3OCH2CH3 (C4H10O, ether with oxygen).
- C and D provide no formulas, failing to represent any isomers.
Final answer: A
Topic: Hydrocarbons
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