Oxidation states of chlorine in products Steps: - Identify X as oxidation state of Cl in NaCl: Na is +1, so Cl is -1; X = -1. - For hot NaOH reaction, identify Y as oxidation state of Cl in NaClO3: NaClO3 is neutral, Na +1, O3 is -6, so Cl is +5; Y = +5. - Compute relation: Y - X = +5 - (-1) = +6, so Y = X + 6. - Verify with cold reaction (not needed for choices, but Y = +1 gives +1 = -1 + 2, absent from options; hot fits D). Why D is correct: - In disproportionation, Cl oxidation state shifts from 0 in Cl2 to -1 (X) and +5 (Y) in hot products, differing by 6 per definition of oxidation number change in balanced equation 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O. Why the others are wrong: - A: Y = X - 5 gives -1 - 5 = -6, but Cl cannot be -6 in hypochlorite or chlorate. - B: Y = X - 4 gives -1 …