A Levels Chemistry (9701)•9701/12/M/J/25
Explanation
Reduction and esterification of carboxylic acids Steps:
- Propanoic acid (CH3CH2COOH) is reduced by LiAlH4 to propan-1-ol (CH3CH2CH2OH), the primary alcohol product P.
- Methanoic acid (HCOOH) undergoes acid-catalyzed esterification with P using concentrated H2SO4 as catalyst.
- The reaction forms the ester by combining the acyl group from methanoic acid and the alkyl group from P.
- Product Q is propyl formate (HCOOCH2CH2CH3); skeletal formulae are CH3CH2CH2OH for P and HC(O)OCH2CH2CH3 for Q.
Why B is correct:
- Not applicable; B shows CH3COOCH3 (methyl acetate), requiring CH3OH and CH3COOH, contradicting the given acids and reduction.
Why the others are wrong:
- A: Shows ethyl formate for Q, using ethanol instead of propan-1-ol.
- C: Q is CH3COOH, an unchanged acid, not an ester product.
- D: Q is HCOOH, the reactant acid, ignoring esterification.
Not enough information. Final answer: Not enough information.
Topic: Carboxylic acids and derivatives
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