Number of deprotonatable OH groups determines ion charge

Steps:

• Sodium metal (Na) reacts with each OH group in alcohols to form alkoxide ions (RO⁻) and H₂, with each OH contributing -1 charge to the organic ion.
• With excess Na, all OH groups deprotonate, so the organic ion charge equals negative the number of OH groups.
• Count OH groups: A has 2, B has 3, C has 2, D has 3.
• No option has 1 OH group, so none produce an organic ion with charge -1.

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