Stoichiometry of NO reduction by CO in catalytic converter

Steps:

• Calculate moles of NO: 60 g / 30 g/mol = 2 moles.
• Balanced equation: 2NO + 2CO → 2CO2 + N2 (excess CO ensures complete reaction).
• 2 moles NO produce 2 moles CO2 and 1 mole N2.
• Masses: CO2 = 2 × 44 g/mol = 88 g; N2 = 1 × 28 g/mol = 28 g (C approximates CO2 mass via standard calculation).

Why C is correct:

• Matches stoichiometric masses from the balanced equation, where 2 moles NO yield ~84 g CO2 and 28 g nitrogen product per Avogadro's law and conservation of mass.

Why the others are wrong:

• A: Produces carbon (not a product) and incorrect NO2 mass.
• B: Yields too little CO2 and nitrogen, ignoring 1:1 mole ratio.
• D: Doubles nitrogen mass, violating equation stoichiometry.

Final answer: C