Redox analysis of ICl hydrolysis Steps:

• In ICl, Cl (more electronegative) is -1, so I is +1.
• Products: HIO3 has I +5 (H +1, 3O -6); I2 has I 0; HCl has Cl -1.
• Some I oxidized (+1 to +5) forming HIO3 (written as HOI); some reduced (+1 to 0) forming I2.
• Cl unchanged at -1; no reduction.

Why B is correct:

• Reduction decreases oxidation number; Cl remains -1 in ICl and HCl, violating the definition.

Why the others are wrong:

• A: Correctly states I (+1) oxidized to oxyiodine product, so not the wrong statement.
• C: I initial state is +1, not -1; false premise makes it invalid choice.
• D: Same as C; incorrect initial state for I.

Final answer: B