Stereoisomers from chiral center and E/Z double bond

Steps:

• Parse structure: CH3-CH=CH-CH(OH)-CH3 has double bond between C2-C3 and OH on C4.
• Double bond shows geometric isomerism: C2 has CH3/H, C3 has H/CH(OH)CH3, yielding E and Z forms.
• C4 is chiral: attached to OH, H, CH3, and CH=CHCH3 (four distinct groups).
• Total: 2 (E/Z) × 2 (R/S at C4) = 4 stereoisomers.

Why C is correct:

• One stereogenic double bond and one chiral center produce 2 × 2 = 4 stereoisomers per standard organic stereochemistry rules.

Why the others are wrong:

• A: Counts only E/Z or only enantiomers, missing the other feature.
• B: No basis for odd number; no meso compound or partial combinations.
• D: Exceeds 4; no additional stereocenters or isomer types present.

Final answer: C