mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Chemistry (9701)•9701/12/M/J/24
Question 34 from 9701/12/M/J/24

Explanation

Limonene has two C=C double bonds requiring hydrogenation

Steps:

  • Calculate degree of unsaturation for C10H16: (2×10 + 2 - 16)/2 = 3.
  • Subtract 1 for the 6-membered ring: 3 - 1 = 2 C=C double bonds.
  • Each C=C bond reacts with 1 mol H2, so 2 mol H2 per mol limonene.
  • At room conditions, 1 mol gas occupies 24 dm³, so 2 × 24 = 48 dm³.

Why C is correct:

  • Matches 2 mol H2 × 24 dm³/mol (molar volume at RTP).

Why the others are wrong:

  • A: Assumes 0.5 mol H2 (ignores actual double bonds).
  • B: Assumes 1 mol H2 (underestimates by one double bond).
  • D: Assumes 3 mol H2 (includes ring as unsaturation).

Final answer: C

Topic: Hydrocarbons

Practice more A Levels Chemistry (9701) questions on mMCQ.me