Highest H:C Ratio in Saturated Oxygen-Containing Compounds

Steps:

• Recall general formulas: alcohols (C_nH_{2n+2}O), aldehydes (C_nH_{2n}O), carboxylic acids (C_nH_{2n}O_2), haloalkanes (C_nH_{2n+1}X).
• Calculate H/C ratios: alcohols ((2n+2)/n = 2 + 2/n), aldehydes (2n/n = 2), carboxylic acids (2n/n = 2), haloalkanes ((2n+1)/n = 2 + 1/n).
• Compare values: alcohols exceed 2 (e.g., 2.5 for n=2), while others are 2 or less.
• Determine alcohols yield the highest ratio due to maximal saturation.

Why A is correct:

• Alcohols follow C_nH_{2n+2}O, retaining the full alkane-like hydrogen count with one oxygen substitution.

Why the others are wrong:

• B: Aldehydes' C_nH_{2n}O formula has two fewer hydrogens than alkanes due to the -CHO group.
• C: Carboxylic acids' C_nH_{2n}O_2 includes an extra oxygen, matching aldehyde H count.
• D: Haloalkanes' C_nH_{2n+1}X replaces one H with halogen, reducing H below alcohol levels.

Final answer: A