A Levels Chemistry (9701)•9701/11/M/J/24

Explanation
C5H10O methyl ketone isomers
Steps:
- NaBH4 reduction adds 2 u to molar mass; 2.32% increase gives Mr(X) ≈ 86 (exact for C5H10O).
- Iodoform test (yellow ppt with I2/OH-) indicates methyl ketone (CH3COR).
- For C5H10O, R = C3H7 (two isomers: n-propyl, isopropyl).
- Yields pentan-2-one (CH3COCH2CH2CH3) and 3-methylbutan-2-one (CH3COCH(CH3)2); both acyclic with one carbonyl.
Why B is correct:
- Exactly two C3H7 isomers fit CH3COC3H7 formula for methyl ketones.
Why the others are wrong:
- A: Ignores two distinct C3H7 structures.
- C: No additional C5 methyl ketone isomers exist.
- D: Exceeds actual count of two.
Final answer: B
Topic: Carbonyl compounds
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