mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Chemistry (9701)•9701/11/M/J/24
Question 34 from 9701/11/M/J/24

Explanation

C5H10O methyl ketone isomers

Steps:

  • NaBH4 reduction adds 2 u to molar mass; 2.32% increase gives Mr(X) ≈ 86 (exact for C5H10O).
  • Iodoform test (yellow ppt with I2/OH-) indicates methyl ketone (CH3COR).
  • For C5H10O, R = C3H7 (two isomers: n-propyl, isopropyl).
  • Yields pentan-2-one (CH3COCH2CH2CH3) and 3-methylbutan-2-one (CH3COCH(CH3)2); both acyclic with one carbonyl.

Why B is correct:

  • Exactly two C3H7 isomers fit CH3COC3H7 formula for methyl ketones.

Why the others are wrong:

  • A: Ignores two distinct C3H7 structures.
  • C: No additional C5 methyl ketone isomers exist.
  • D: Exceeds actual count of two.

Final answer: B

Topic: Carbonyl compounds

Practice more A Levels Chemistry (9701) questions on mMCQ.me