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A Levels Chemistry (9701)•9701/13/M/J/23
Question 37 from 9701/13/M/J/23

Explanation

Ester Structure Analysis for Isomer and Alcohol Classification

Steps:

  • Examine the double bond in the acid-derived chain of the ester; cis isomer has substituents on the same side.
  • Confirm trans would have substituents on opposite sides, but the structure aligns with cis.
  • Identify the alcohol-derived alkyl group; the carbon attached to the ester oxygen has two alkyl substituents.
  • Classify this carbon: two substituents indicate secondary alcohol.

Why A is correct:

  • The ester's double bond shows cis geometry (same-side substituents per alkene isomerism rules), and the alcohol's -CH(R1)(R2)-O- linkage defines a secondary alcohol (carbon with two carbons attached).

Why the others are wrong:

  • B: Alcohol is secondary, not tertiary (tertiary requires three alkyl groups on the oxygen-attached carbon).
  • C: Geometrical isomer is cis, not trans (trans has opposite-side substituents).
  • D: Isomer is cis (not trans) and alcohol is secondary (not tertiary).

Final answer: A

Topic: Carboxylic acids and derivatives

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