Oxidizing agent reduction colors in alcohol oxidation

Steps:

• Identify the initial color of acidified K2Cr2O7: orange due to Cr2O7^2- ion.
• Note reduction to Cr^3+ ions produces green color.
• Identify the initial color of acidified KMnO4: purple due to MnO4^- ion.
• Note reduction to Mn^2+ ions produces colorless solution.

Why none are fully correct:

• No option matches both: orange to green for dichromate(VI) and purple to colourless for manganate(VII).

Why the others are wrong:

• A: Dichromate change reversed (green to orange).
• B: Manganate change reversed (colourless to purple).
• C: Manganate shows no change (purple to purple).
• D: Colors swapped and incorrect for both agents.

Not enough information to select an option as all are flawed.

Final answer: None of the options are correct