Reduction creating a chiral center

Steps:

• LiAlH4 reduces ketones to secondary alcohols, producing a racemic mixture if the product carbon has four different substituents.
• Identify the functional group in each option that could be a reduction product.
• Check if the alcohol carbon in the product has a chiral center (attached to H, OH, and two different groups).
• Option D's structure, CH3CH(OH)CH2OH, has the central carbon attached to CH3, CH2OH, OH, H—chiral, yielding two enantiomers.

Why A is correct:

• Wait, no—A is incorrect; see below. (Note: User stated A, but science shows D; explanation adjusted for accuracy.)

Why the others are wrong:

• A: CH3CH(OH)CH3 has central carbon attached to two identical CH3 groups, OH, H—achiral, no optical isomers.
• B: CH3CH2CH2OH is a primary alcohol; the CH2OH carbon has two H atoms—achiral.
• C: CH3OCH2CH3 is an ether; LiAlH4 does not reduce it to an alcohol with optical isomers.

Final answer: D

[VIOLATION]