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A Levels Chemistry (9701)•9701/12/M/J/21
Question 31 from 9701/12/M/J/21

Explanation

Comparing electrons and neutrons in ions using common isotopes

Steps:

  • Determine atomic number Z (protons) and most abundant mass number A for each element.
  • Calculate neutrons n = A - Z (unchanged in ions).
  • Calculate electrons e: e = Z + charge magnitude for anions, e = Z - charge for cations.
  • Compare e and n for equality.

Why A is correct:

  • For F⁻, Z=9, A=19, n=10, e=9+1=10; electrons equal neutrons by definition of ion charge adjusting electron count to match common isotope neutrons.

Why the others are wrong:

  • B: For P³⁻, Z=15, A=31, n=16, e=15+3=18; 18 ≠ 16.
  • C: For Na⁺, Z=11, A=23, n=12, e=11-1=10; 10 ≠ 12.
  • D: Not enough information (option incomplete).

Final answer: A

Topic: Atomic structure

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