Propene reaction products via addition mechanisms

Steps:

• Identify propene as CH₃CH=CH₂, an unsymmetrical alkene.
• Evaluate each reagent's reaction: KMnO₄ variants for oxidation, HCl for electrophilic addition, steam for hydration.
• Apply Markovnikov's rule where applicable: H adds to carbon with more hydrogens.
• Match predicted product to table description.

Why C is correct:

• HCl undergoes electrophilic addition following Markovnikov's rule, yielding CH₃CHClCH₃ (2-chloropropane) as H⁺ adds to terminal carbon.

Why the others are wrong:

• A: Hot acidified KMnO₄ causes oxidative cleavage to CH₃COOH + HCOOH, not propan-1,2-diol.
• B: Cold dilute KMnO₄ performs syn dihydroxylation to propan-1,2-diol, not 2-bromopropane.
• D: Steam (acid-catalyzed hydration) follows Markovnikov's rule to propan-2-ol, not propan-1-ol.

Final answer: C