Silver chloride dissolves in excess ammonia Steps:

• Mixing equal volumes and concentrations of NaCl and AgNO₃ produces 0.00025 mol AgCl, a white precipitate.
• AgCl reacts with ammonia: AgCl(s) + 2NH₃(aq) ⇌ [Ag(NH₃)₂]⁺(aq) + Cl⁻(aq).
• With excess concentrated ammonia, the equilibrium shifts right, dissolving the precipitate completely.
• Result: clear solution with no visible precipitate.

Why D is correct:

• AgCl is soluble in excess ammonia due to formation of the stable diamminesilver(I) complex, per coordination chemistry principles.

Why the others are wrong:

• A: Cream precipitate forms with bromide ions, not chloride.
• B: White precipitate is initial AgCl before ammonia addition.
• C: Yellow precipitate is silver iodide, insoluble in ammonia.

Final answer: D