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A Levels Chemistry (9701)•9701/13/M/J/20
Question 20 from 9701/13/M/J/20

Explanation

Electrophilic addition of HBr to trans-2-butene yields chiral and achiral products via different mechanisms Steps:

  • Trans-2-butene (CH₃CH=CHCH₃) undergoes electrophilic addition with HBr via carbocation intermediate, following Markovnikov's rule.
  • H⁺ adds to C2 or C3 (equivalent), forming a secondary carbocation at C3 or C2 (CH₃CH₂CH⁺CH₃).
  • Br⁻ attacks the planar carbocation from either side, producing (R)-2-bromobutane and (S)-2-bromobutane.
  • In free radical mechanism (possible with trace peroxides), Br• adds first, but symmetry still favors 2-bromobutane; however, minor anti-Markovnikov path can yield 1-bromobutane (CH₃CH₂CH₂CH₂Br).

Why C is correct:

  • Three distinct products form: two enantiomers of 2-bromobutane (chiral, from ionic mechanism) and 1-bromobutane (achiral, from potential free radical path), per Markovnikov's rule and free radical addition principles.

Why the others are wrong:

  • A: Ignores stereoisomers and minor product; only one constitutional isomer under strict ionic conditions.
  • B: Accounts for racemic 2-bromobutane but misses possible 1-bromobutane.
  • D: Overcounts; no additional constitutional or stereoisomers beyond these three.

Final answer: C

Topic: Hydrocarbons

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