Stoichiometric air volume for complete butane combustion

Steps:

• Balanced equation: C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O (13/2 O₂ per butane).
• O₂ volume needed: 10 cm³ butane × 6.5 = 65 cm³ O₂ (volumes proportional at room conditions).
• Air volume: 65 cm³ O₂ / 0.21 = 310 cm³ air.
• Minimum volume is 310 cm³ for complete combustion.

Why D is correct:

• D equals the stoichiometric air volume from ideal gas law volume ratios and 21% O₂ composition.

Why the others are wrong:

• A: Underestimates O₂ need, ignoring full stoichiometry.
• B: Arbitrary low value, no basis in equation or air percentage.
• C: Matches O₂ volume only, forgets to divide by air's 21% O₂ fraction.

Final answer: D