A Levels Chemistry (9701)•9701/12/M/J/19

Explanation
Iodoform test distinguishes alcohols with CH3CH(OH)- structure
Steps:
- Ethanol (CH3CH2OH) and propanol (CH3CH2CH2OH) are both primary alcohols but differ in carbon chain.
- Iodoform test (I2/NaOH) requires CH3CH(OH)R or CH3COR for yellow precipitate formation.
- Ethanol fits CH3CH(OH)- and yields iodoform; propanol (CH3CH2CH2OH) does not.
- Other tests react similarly for both or not at all.
Why B is correct:
- I2/NaOH performs iodoform reaction; ethanol oxidizes to acetaldehyde (CH3CHO), forming CHI3 precipitate, while propanol forms propanal (CH3CH2CHO) without methyl carbonyl group.
Why the others are wrong:
- A: 2,4-Dinitrophenylhydrazine tests for carbonyls; neither alcohol has one.
- C: K2Cr2O7/H2SO4 oxidizes both primary alcohols to carboxylic acids with color change.
- D: Tollen's reagent tests for aldehydes; neither is an aldehyde.
Final answer: B
Topic: Hydroxy compounds
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