Oxidation states unchanged in hydrolysis

Steps:

• Assign oxidation states: In XeF6, Xe is +6 (6F at -1 each); in H2O, H is +1, O is -2.
• Products: In XeO3, Xe is +6 (3O at -2 each); in HF, H is +1, F is -1.
• Compare: Xe remains +6, H +1, O -2, F -1—no changes.
• Conclude: No electron transfer, so not redox.

Why D is correct:

• Redox reactions require oxidation state changes (definition: transfer of electrons between species).

Why the others are wrong:

• A: Hydrogen oxidation state unchanged (+1 in H2O and HF).
• B: Oxygen oxidation state unchanged (-2 in H2O and XeO3).
• C: Xenon oxidation state unchanged (+6 in XeF6 and XeO3).

Final answer: D